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Units and Measurement — NEET & JEE MCQs with answers

NCERT Class 11 · Physics · Ch 110 free questions515 in the full bank
Physical quantities are measured by comparing with internationally accepted reference standards called units; the SI system defines seven base units from which all derived units are constructed. The chapter covers significant figures, dimensional analysis, and the use of dimensions to check and derive physical relationships.

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Free practice questions

Question 1 · 1.2 The International System of Units · Hard
In the SI definition of the kelvin, the kilogram, metre and second (in kg m$^2$ s$^{-2}$ K$^{-1}$) are themselves defined in terms of:
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Answer: C — NCERT Table 1.1 (kelvin): 'where the kilogram, metre and second are defined in terms of h, c and $\Delta\nu_{Cs}$.'

NCERT Class 11 Physics · Ch 1 · 1.2 The International System of Units

Question 2 · 1.3 Significant Figures · Medium
5.74 g of a substance occupies $1.2$ cm$^3$. Its density expressed to correct significant figures is:
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Answer: A — 5.74/1.2 = 4.783... Rounded to two significant figures (least, from 1.2) gives 4.8 g cm⁻³. (NCERT Example 1.2.)

NCERT Class 11 Physics · Ch 1 · 1.3 Significant Figures

Question 3 · 1.4 Dimensions of Physical Quantities · Easy
The dimension $[A]$ in NCERT's seven-dimension scheme corresponds to which base quantity?
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Answer: D — NCERT: electric current has dimension $[A]$ (ampere).

NCERT Class 11 Physics · Ch 1 · 1.4 Dimensions of Physical Quantities

Question 4 · 1.5 Dimensional Formulae and Dimensional Equations · Medium
A test of consistency of dimensions, according to NCERT, has the advantage over a test of consistency of units that:
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Answer: A — NCERT 1.6.1 states a test of dimensions tells no more nor less than a test of units, but has the advantage that we need not commit to a particular choice of units, nor worry about conversions among multiples and sub-multiples.

NCERT Class 11 Physics · Ch 1 · 1.5 Dimensional Formulae and Dimensional Equations

Question 5 · 1.6 Dimensional Analysis and its Applications · Hard
Apply the reasoning of Example 1.4 to the formula $K = \tfrac{1}{2}mv^{2} + m a h$, where $h$ is a height. On the basis of dimensional arguments alone, this formula:
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Answer: C — $[m a h] = [M][L\,T^{-2}][L] = [M\,L^2\,T^{-2}]$, the same as $[\tfrac12 mv^2]$, so the sum is allowed and has the dimensions of $K$. Formula (e) on p.9 lost its 'proper dimensions' only because $ma$ is $[M\,L\,T^{-2}]$. Passing the test does not prove a formula right (p.8), so it is merely 'not ruled out'.

NCERT Class 11 Physics Part-I · Ch 1 · 1.6.1 Checking the Dimensional Consistency of Equations · p.9

Question 6 · 1.1 Introduction · Easy
Fundamental or base units are the units assigned to the
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Answer: B — NCERT: 'The units for the fundamental or base quantities are called fundamental or base units.'

NCERT Class 11 Physics · Ch 1 · 1.1 Introduction

Question 7 · 1.2 The International System of Units · Easy
In the CGS system, the base units for length, mass and time were respectively:
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Answer: B — NCERT 1.2: 'In CGS system they were centimetre, gram and second respectively.'

NCERT Class 11 Physics · Ch 1 · 1.2 The International System of Units

Question 8 · 1.3 Significant Figures · Medium
Round off $0.104$ taken as $0.1044$ would, on reciprocal to three significant figures, retrieve which original value?
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Answer: C — NCERT: writing 1/9.58 = 0.1044 (one extra digit) and then taking the reciprocal to three significant figures retrieves the original 9.58.

NCERT Class 11 Physics · Ch 1 · 1.3 Significant Figures

Question 9 · 1.5 Dimensional Formulae and Dimensional Equations · Medium
According to NCERT, if an equation fails the dimensional consistency test, then it is:
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Answer: B — NCERT 1.6.1: if an equation fails the consistency test, it is proved wrong; but if it passes, it is not proved right.

NCERT Class 11 Physics · Ch 1 · 1.5 Dimensional Formulae and Dimensional Equations

Question 10 · 1.4 Dimensions of Physical Quantities · Easy
Volume is the product of length, breadth and height (three lengths). Its dimensional formula is:
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Answer: C — NCERT: dimensions of volume = $[L]\times[L]\times[L]=[L]^3=[L^3]$, with zero dimension in mass and time, i.e. $[M^0 L^3 T^0]$.

NCERT Class 11 Physics · Ch 1 · 1.4 Dimensions of Physical Quantities

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