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Electromagnetic Waves — NEET & JEE MCQs with answers

NCERT Class 12 · Physics · Ch 810 free questions538 in the full bank
Maxwell showed that a time-varying electric field produces a magnetic field (displacement current), just as a time-varying magnetic field produces an electric field. This led to the prediction of electromagnetic (EM) waves travelling at the speed of light $c = 1/\sqrt{\mu0\varepsilon0} \approx 3\times10^8$ m/s, unifying electricity, magnetism and light. The chapter covers displacement current, the nature of EM waves, and the electromagnetic spectrum.

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Free practice questions

Question 1 · 8.3 Electromagnetic Waves · Medium
The electric field amplitude of an electromagnetic wave in vacuum is $E_0=4.5$ V/m. Using $c=3\times10^{8}$ m/s, the magnetic field amplitude is:
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Answer: B — $B_0=E_0/c=4.5/(3\times10^{8})=1.5\times10^{-8}$ T.

NCERT Class 12 Physics Ch 8 ("B0 = (E0/c)")

Question 2 · 8.4 Electromagnetic Spectrum · Easy
The electromagnetic spectrum extends, in order of increasing wavelength, up to a longest wavelength of about $10^{6}$ m. Which band corresponds to this longest-wavelength end?
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Answer: D — The spectrum runs by increasing wavelength from about $10^{-12}$ m (gamma rays) to about $10^{6}$ m. Radio waves occupy the long-wavelength extreme, so the $\sim 10^{6}$ m end corresponds to radio waves.

NCERT Class 12 Physics Ch 8 ("in order of increasing wavelength")

Question 3 · 8.1 Introduction · Medium
Whose technological use of electromagnetic waves led to the revolution in communication?
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Answer: A — The technological use by Marconi and others led to the revolution in communication.

NCERT Class 12 Physics Ch 8 ("revolution in communication")

Question 4 · 8.2 Displacement Current · Medium
If the displacement current in a region is $1\times10^{-2}$ A, then using $i_d=\varepsilon_0\,d\Phi_E/dt$ the rate of change of electric flux is:
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Answer: D — $\dfrac{d\Phi_E}{dt}=\dfrac{i_d}{\varepsilon_0}=\dfrac{1\times10^{-2}}{8.85\times10^{-12}}=1.13\times10^{9}$ V·m/s.

NCERT Class 12 Physics Ch 8 ("This implies that for consistency,")

Question 5 · 8.4 Electromagnetic Spectrum · Easy
According to NCERT, which celestial body is described as an important source of ultraviolet light?
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Answer: B — The text explicitly states that the sun is an important source of ultraviolet light, most of which is fortunately absorbed in the ozone layer.

NCERT Class 12 Physics Ch 8 ("The sun is an important source of ultraviolet")

Question 6 · 8.3 Electromagnetic Waves · Easy
The fact that the electric field of the capacitor is perpendicular to the plates while the magnetic field it produces is along a circle parallel to the plates shows that $\mathbf{B}$ and $\mathbf{E}$ are perpendicular. NCERT states this is:
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Answer: B — After noting that in the capacitor case $\mathbf{B}$ and $\mathbf{E}$ are perpendicular, NCERT states "This is a general feature" — mutual perpendicularity of the fields holds for all electromagnetic waves.

NCERT Class 12 Physics Ch 8 ("This is a general feature")

Question 7 · 8.2 Displacement Current · Medium
The electric flux between the plates of a charging capacitor changes at a rate of $3\times10^{7}$ V·m/s. The displacement current between the plates is:
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Answer: D — $i_d=\varepsilon_0\dfrac{d\Phi_E}{dt}=8.85\times10^{-12}\times 3\times10^{7}=2.65\times10^{-4}$ A.

NCERT Class 12 Physics Ch 8 ("This implies that for consistency,")

Question 8 · 8.1 Introduction · Medium
Maxwell (1831-1879) argued that the converse of Faraday's result 'was indeed the case'. This converse states that:
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Answer: B — The converse is that a time-varying electric field generates a magnetic field.

NCERT Class 12 Physics Ch 8 ("argued that this was indeed the case")

Question 9 · 8.3 Electromagnetic Waves · Easy
A stationary electric charge produces only:
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Answer: A — NCERT: neither stationary charges nor charges in uniform motion can be sources of electromagnetic waves; the former produces only electrostatic fields.

NCERT Class 12 Physics Ch 8 ("The former produces only electrostatic fields")

Question 10 · 8.2 Displacement Current · Medium
A capacitor is being charged by a constant conduction current of $1.5\times10^{-1}$ A in the connecting wires. The displacement current between the plates is:
Show answer
Answer: A — For a charging capacitor the displacement current equals the conduction current in magnitude, so $i_d=i_c=1.5\times10^{-1}$ A.

NCERT Class 12 Physics Ch 8 ("so that id = i")

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